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2p^2-11p-63=0
a = 2; b = -11; c = -63;
Δ = b2-4ac
Δ = -112-4·2·(-63)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-25}{2*2}=\frac{-14}{4} =-3+1/2 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+25}{2*2}=\frac{36}{4} =9 $
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